Question

construct a triangle of sides 4cm,5cm and 6cm and then a triangle similar to it whose sides are 2/3 of the corresponding sides of the the first triangle ​

Answer 1

Answer:

Let's first construct △ABC with sides 4cm,5cm,6cm

Steps to draw △ABC

1. Draw base AB of side 4cm.

2. With A as centre , and 5cm as radius, draw an arc.

3. With B as centre , and 6cm as radius ,draw an arc.

4. Let C be the point where two points intersect.

5. Join AC and BC

Thus △ABC is the required triangle

Now, lets make the triangle similar to this named as △PQR whose sides are

3

2

of the corresponding sides so the sides will become

3

8

cm,

3

10

cm,4cm

Steps to draw △PQR

1. Draw base PQ of side

3

8

cm.

2. With P as centre , and

3

10

cm. as radius, draw an arc.

3. With Q as centre , and 4cm as radius ,draw an arc.

4. Let R be the point where two points intersect.

5. Join PQ and PR

Thus △PQR is the required triangle

Explanation

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