Question

construct a triangle of sides 4cm, 5cm and 6cm. Construct another triangle similar to it whose sides are 3/2 of the corresponding sides of the first triangle and justify the construction.​

Answer 1

Answer:

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Step-by-step explanation:

Let's first construct △ABC with sides 4cm,5cm,6cm

Steps to draw △ABC

1. Draw base AB of side 4cm.

2. With A as centre , and 5cm as radius, draw an arc.

3. With B as centre , and 6cm as radius ,draw an arc.

4. Let C be the point where two points intersect.

5. Join AC and BC

Thus △ABC is the required triangle

Now, lets make the triangle similar to this named as △PQR  whose sides are   2/3 of the corresponding sides so the sides will become 8/3 cm,  cm,4cm

Steps to draw △PQR

1. Draw base PQ of side   8/3cm.

2. With P as centre , and   10/3 cm. as radius, draw an arc.

3. With Q as centre , and 4cm as radius ,draw an arc.

4. Let R be the point where two points intersect.

5. Join PQ and PR

Thus △PQR is the required triangle