Question

Construct a triangle of sides 5 cm, 3 cm and 6 cm and then a triangle similar to it whose sides are 3/4of the corresponding sides of the first triangle​

Answer 1

Answer:

Step I: AB = 6 cm is drawn. Step II: With A as a centre and radius equal to 4cm, an arc is draw. Step III: Again, with B as a centre and radius equal to 5 cm an arc is drawn on same side of AB intersecting previous arc at C. Step IV: AC and BC are joined to form ΔABC.

Step-by-step explanation:

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Answer 2

Answer:

Step I: AB = 6 cm is drawn.

Step II: With A as a centre and radius equal to 4cm, an arc is draw.

Step III: Again, with B as a centre and radius equal to 5 cm an arc is drawn on same side of AB intersecting previous arc at C.

Step IV: AC and BC are joined to form ΔABC. And by the need of this step we'll get our desired triangle.

Step-by-step explanation:

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