Construct a triangle of sides 5 cm, 6 cm and 8 cm, then construct a triangle similar to it whose sides are 3/4 of the corresponding sides of first triangle.
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I hope it helps because I am answering this question at 1:36 AM now :-) mark me brainlist, please
Step-by-step explanation:
step of construction -
1) Make base BC as 8 cm
2) take A radius of 6 cm in compass and draw an arc
3)Now, take the radius of 5 cm and cut an arc
4) name point of intersection as A and join AB and AC
5) ABC is the required triangle
6l Now repeat Similar steps but
with 3/4 of value to construct the second triangle
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