Question

construct a triangle of sides 5cm 6cm and 7cm and then a triangle similar to it whose sides are 2/3 Times of the corresponding sides of first triangle 2 1/2
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Answer 1

Answer:

Step-by-step explanation:

Making the triangle

Draw a line segment AB = 5 cm

Draw an arc at 6 cm from point A.

Draw an arc at 7 cm from point B so that it intersects the previous arc.

Joint the point of intersection from A and B.

This gives the required triangle ABC.

Dividing the base:

Draw a ray AX at an acute angle from AB

Plot three points on AX so that; AA  1

= A  1

A2

= A  2

A 3

Join A3to B.

Draw a line from point A  2

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 so that this line is parallel to A  3

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B and intersects AB at point B'

Draw a line from point B' parallel to BC so that this line intersects AC at point C'

⇒△AB  ′ C  ′  is the required triangle