construct a triangle of sides 8,8and10 cms, then construct a triangle similar to it whose sides are 3/5of the corresponding sides of first triangle
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Solution: Draw a line segment AB = 7.6 cm.
Draw a ray AX which makes an acute angle with AB.
Locate 13 points (5 + 8) A1, A2, A3, …….A13 on AX so that;
AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6= A6A7 = A7A8 = A8A9 = A9A10 = A10A11 = A11A12 = A12A13
Draw a ray AX which makes an acute angle with AB.
Locate 13 points (5 + 8) A1, A2, A3, …….A13 on AX so that;
AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6= A6A7 = A7A8 = A8A9 = A9A10 = A10A11 = A11A12 = A12A13
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steps of construction :-
- Draw ΔABC with AB=8cm, BC=8cm and AC=10cm
- Draw a ray Bx making on acute angle with BC on the side opposite to vertex A.
- Mark three points B1,B2 and B3 on Bx such that BB1=B1B2=B2B3
- join B3, C
- Draw a line parallel to B3C through B2. meeting BC at C¹
- Draw a line parallel to BA through C¹ meeting BA at A¹
- ΔA¹BC¹ is the required triangle with scale factor 3/5.
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