Question

construct a triangle of sides 8,8and10 cms, then construct a triangle similar to it whose sides are 3/5of the corresponding sides of first triangle

Answer 1

Solution: Draw a line segment AB = 7.6 cm.

Draw a ray AX which makes an acute angle with AB.

Locate 13 points (5 + 8) A1, A2, A3, …….A13 on AX so that;

AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6= A6A7 = A7A8 = A8A9 = A9A10 = A10A11 = A11A12 = A12A13

Answer 2

$\huge{\mathrm{\star{\underline {\underline {\red{Answer:-}}}}}}$

steps of construction :-

1. Draw ΔABC with AB=8cm, BC=8cm and AC=10cm
2. Draw a ray Bx making on acute angle with BC on the side opposite to vertex A.
3. Mark three points B1,B2 and B3 on Bx such that BB1=B1B2=B2B3
4. join B3, C
5. Draw a line parallel to B3C through B2. meeting BC at C¹
6. Draw a line parallel to BA through C¹ meeting BA at A¹
7. ΔA¹BC¹ is the required triangle with scale factor 3/5.

I have attached your answer..

hope it helps u.. ✌✌✌

mark my answer to brainliest please please... humble request.. please...