Question

construct a triangle∆ par,l ( pq)= 5.5cm mla=50°, l( pr)=5 cm
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Answer 1

Answer:

Draw a line segment DE=4.5cm

Draw a line segment DE=4.5cm⇒ Take E as center with radius 6.5cm and draw an arc.

Draw a line segment DE=4.5cm⇒ Take E as center with radius 6.5cm and draw an arc.⇒ Take D as center with radius 7.2cm and draw an arc meeting previous arc at point F

Draw a line segment DE=4.5cm⇒ Take E as center with radius 6.5cm and draw an arc.⇒ Take D as center with radius 7.2cm and draw an arc meeting previous arc at point F⇒ Take E as center with radius 7.8cm and draw an arc.

Draw a line segment DE=4.5cm⇒ Take E as center with radius 6.5cm and draw an arc.⇒ Take D as center with radius 7.2cm and draw an arc meeting previous arc at point F⇒ Take E as center with radius 7.8cm and draw an arc.⇒ Take D as center with radius 5.5cm and draw an arc meeting previous arc at point G

Draw a line segment DE=4.5cm⇒ Take E as center with radius 6.5cm and draw an arc.⇒ Take D as center with radius 7.2cm and draw an arc meeting previous arc at point F⇒ Take E as center with radius 7.8cm and draw an arc.⇒ Take D as center with radius 5.5cm and draw an arc meeting previous arc at point G⇒ Join EF,DF,FG and DG

Draw a line segment DE=4.5cm⇒ Take E as center with radius 6.5cm and draw an arc.⇒ Take D as center with radius 7.2cm and draw an arc meeting previous arc at point F⇒ Take E as center with radius 7.8cm and draw an arc.⇒ Take D as center with radius 5.5cm and draw an arc meeting previous arc at point G⇒ Join EF,DF,FG and DG∴ DEFG is required quadrilateral.

Step-by-step explanation:

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