construct a triangle perimeter 12cm and are sides are in the ratio 3:4:5
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Step-by-step explanation: Let the sides be 3 cm ,4cm and 5cm.(because it is the only case where perimeter is 12 cm.I hope you can do it then. If not don't hesitate to ask.
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Draw a line of 5 cm. Take a compass draw an arc of 3 cm from one end of the line and then draw ana rc of 4cm from the other end . From the point of intersection of these arcs join the ends of line. Here you get your Triangle.
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SOLUTION;...✍️
Given, A triangle of perimeter=12cm&
sides = 3:4:5
Now, let the sides be x
=3x+4x+5x=12{Perimeter∆= Sum of three sides}
=12x=12
=x= 12/12
=x= 1.
So,
1st side= 3x= 3×1= 3cm
2nd side= 4x=4×1=4cm
3rd side= 5x= 5×1= 5cm.
✓✓MARK BRAINLIEST✓✓✓
Given, A triangle of perimeter=12cm&
sides = 3:4:5
Now, let the sides be x
=3x+4x+5x=12{Perimeter∆= Sum of three sides}
=12x=12
=x= 12/12
=x= 1.
So,
1st side= 3x= 3×1= 3cm
2nd side= 4x=4×1=4cm
3rd side= 5x= 5×1= 5cm.
✓✓MARK BRAINLIEST✓✓✓
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