Question

Construct a triangle POS such that PQ = 4.cm. PS = 4 cm and SQ = 5.4 cm Construct another triangle
P'QS' similar to triangle PQS with side SQ = 7.5 cm.
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Answer 1

ΔPQS  is constructed such that PQ = 4.cm. PS = 4 cm and SQ = 5.4 cm

Step-by-step explanation:

Step 1 : Draw a Line segment PQ  = 4 cm using ruler

Step 2 : Draw an arc Taking P as center & radius = 4 cm using compass

Step 3 : Draw an arc taking Q as center & Radius = 5.4 cm such that it intersect arc drawn in step 2 at S

Step 4 : Join PS & QS

ΔPQS  is constructed

to Construct ΔP'QS'

Step 1 :Extend  QS  to QS' = 7.5 cm

Step 2 : Extend QP

Step 3 : Draw a line parallel to PS such  that it passes through S' and cut extended QP at point P'

ΔP'QS'  is constructed

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