construct a triangle PQ=4.5 cm RP=5.8 RPQ=60⁰
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Answer:"1. Draw a line segment PQ = 4.5 cm
2. Take a compass and keeping Q as a centre construct an angle of 60 degrees.
3. Now take the radius of 3 cm, draw an arc on the 60-degree angle line. The intersection point of the 3 cm arc and 6 degrees will be R.
4. As per the supplementary property of a parallelogram, SPQ + PQR = 180. Hence draw an angle of 120 degrees on point P.
5. Now draw an arc of 3 cm and mark it as S
6. Join PQRS to form a parallelogram.
Step-by-step explanation:
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