Math, asked by mailtopranavaram, 10 months ago

construct a triangle PQR ,given PQ=3 cm ,QR =5.5cms and angleQ60 degree

Answers

Answered by tjsmohadikar
2

Answer:

FOLLOW STEPS

Step-by-step explanation:

draw a line QR = 5.5 Cms.

measure 3 cm in compass and draw an arc from point Q.

Measure an angle of 60 degree from point Q

draw a line from point Q to angle marked on 60 degree

draw a line from a point of intersection of arc and angle line to point R

Hence triangle PQR Constructed.

Answered by pandeyntpc
0

Answer:

Step-by-step explanation:

Step 1 - Construct PQ = 3 cm with your ruler.

Step 2 - With Q as center, draw an arc of any radius intersecting PQ at A.

Step 3 - With A as center, and the same radius intersect the previous arc at B.

Step 4 - Join ray QB.

Step 5 - With Q as center and 5.5 cm as radius, intersect the ray QB and mark the intersecting point as R.

Step 6 - Join PR.

PQR is the required triangle.

Hope it helps!!

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