Construct a triangle PQR,given that PQ=3cm ,QR=5.5cm and triangle PQR
=60
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Step-by-step explanation:
Steps of Construction:
(i) Draw a line segment that is sufficiently long using a ruler.
(ii) Locate points Q and R on it such that QR=5.2cm.
(iii) At Q, construct a line segment QM, sufficiently large, such that ∠MQR at 60
∘
use protractor to measure 60
∘
(iv) With Q as centre and radius 4cm, draw the line cutting QM at P, join PR.
Then PQR is the required triangle.
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