Question

Construct a triangle PQR given that PQ=4.9 cm , < = 45° and < = 60°. Measure < .​

Answer 1

Step-by-step explanation:

Step 1: Draw a line segment PQ = 4.9 cm

Step 1: Draw a line segment PQ = 4.9 cm Step 2: Draw an angle of 45° at P on PQ using protector

Step 1: Draw a line segment PQ = 4.9 cm Step 2: Draw an angle of 45° at P on PQ using protectorStep 3: Draw an angle of 60° at Q on PQ using protector

Step 1: Draw a line segment PQ = 4.9 cm Step 2: Draw an angle of 45° at P on PQ using protectorStep 3: Draw an angle of 60° at Q on PQ using protectorDrawn angles in step 2 & 3 intersects at R

Step 1: Draw a line segment PQ = 4.9 cm Step 2: Draw an angle of 45° at P on PQ using protectorStep 3: Draw an angle of 60° at Q on PQ using protectorDrawn angles in step 2 & 3 intersects at RAngle PQR is constructed

Step 1: Draw a line segment PQ = 4.9 cm Step 2: Draw an angle of 45° at P on PQ using protectorStep 3: Draw an angle of 60° at Q on PQ using protectorDrawn angles in step 2 & 3 intersects at RAngle PQR is constructedAngle ARE Measured by protector = 75°

=> Angle R = 75°

∠P+∠Q+∠R=180

P+∠Q+∠R=180 ∘

P+∠Q+∠R=180 ∘

P+∠Q+∠R=180 ∘ 45+60+∠R=180

180 - 105

∠R=75

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Answer 2

Hii

Given

=Construct a triangle PQR given that PQ=4.9 cm , < = 45° and < = 60°. Measure < .

To find

= Construct a triangle measure.

Answer

75.

. See in attachment.

Step by step explanation

• Draw a line segment PQ.= 4.•9cm.
• At P, draw a ray making an angle of 45°.
• At q draw another ray making an angle of 60° which intersects the first ray at R.
• ∆pqR =180°
• ∆pqR=60+45-180
• ∆pqR=105-180
• ∆pqR=75.
• ∆pqR=75 answer.

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