Question

construct a triangle PQR given that QR =6cm, QR=6cm, /_Q=45*and QP-PR =2.5 cm​

Answer 1

Step-by-step explanation:

Draw the base QR of length 3 cm.

Make an angle XQR = 45° at point Q of base QR.

Cut the line segment QS =QP- PR = 2 cm from the ray QX.

Join SR and draw the perpendicular bisector of SR say AB.

Let bisector AB intersect QX at P. Join PR Thus, ΔPQR is the required triangle.