Question

Construct a triangle PQR in which angle angleQ=60°,angleR=90°and PQ+QR+RP=11cm

Answer 1

Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.

Step 2: Draw an angle of 60° at P and an angle of 45° at Q.

Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.

Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.

Step 5: Join AB and AC.

∴ ΔABC is the required triangle.

I hope you understand