construct a triangle PQR in which angle r =45°,angle q =60° and PQ+QR+RP=11cm
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✴hy✴
✴here is your answer ✴
✴Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.
✴Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
✴Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
✴Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
✴Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
I hope you understand
✴here is your answer ✴
✴Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.
✴Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
✴Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
✴Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
✴Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
I hope you understand
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