Question

construct a triangle pqr in which pq=4 cm angle p=60 and bc-ac=11.5cm​

Answer 1

Answer:

It is given that BC - AC = 11.5 cm

i.e. BC > AC

Steps of Construction:

1. Draw a line segment AB of length 4 cm

2. Draw an angle of 60° from point A

3. From Ray AX, cut off the line segment AD = 11.5 cm

4. Join D to B.

5. Draw the perpendicular bisector of DB.

6. Extend side bisector of DB and it intersects the line AD at point C.

7. Join B to C.

Now, ABC is a required triangle.

Step-by-step explanation:

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