Math, asked by xpertgamer1033, 1 day ago

construct a triangle PQR in which PQ=5cm,angle=105° and PR+QR=8cm​

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Answered by nirzaranitin
0

PQR +QRP+RPQ=180

105+ 40+ RPQ=180

145+ RPQ=180

RPQ= 180-145

RPQ= 35

LET DRAW A LINE PQ = 5CM

DRAW ANGLE P = 35°

DRAW ANGLE Q = 105°

FINALLY THEY INTERSECT EACH OTHER AT POINT R= 40°

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