Question

Construct a triangle PQR, in which PQ = 6 cm, QR = 7 cm and PR = 8 cm. Then construct another triangle whose sides are $\frac{4}{5}$ times the corresponding sides of ΔPQR.

Answer 1

1st take base PR 8 cm then with rounder mark 7cm from R and 6cm from Q then the point at which they intersect throght that pt joint the lines of PQ n of QR.

u'll get triangle PQR.

then Q draw line down wards with any angle.

then take compass choose appropriate angle make 5 arcs on that line.

name those lines as Q1, q2 and so on joinQ5 with R .

then throught that angle which u hake taken in compass go on pts Q4 n Q5 make arc .

take radius of Q5 arc and go on Q4 mark that angle

ull see intersecting pt

then make line from Q4 and that interceting pt . join those line .

do the sae process on R n the pt which u get on line QR .

join that line.

u will get another triangle.

hope u may got ir