construct a triangle pqr in which PQ is equal to 6.5 CM QR is equal to 5 cm and PR is equal to 5.5 CM
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taking P as centre and measure 5cm , cut an arc . taking Q as centre and measure 6.5 cm , cut an arc name the point meeting as R . PQR is the required triangle .
Step 1: Draw a line segment PQ = 5.5cm using ruler
Step 2: Taking compass width = 6.5 cm and taking Q as center draw an arc
Step 3: Taking compass width = 5 cm & taking P as center draw an arc such that it intersects arc drawn in step 2 at R
Step 4: Join PR & QR
APQR is constructed in which pq
=5.5cm ,qr-6.5 cm,rp=5cm
Hope it's helpful
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