construct a triangle pqr in which pq is equal to 8 cm qr is equal to 7 cm and angle q is equal to 45 degree. draw a perpendicular bisector of qr... please tell me the correct solution...
Answers
Answer:
1) Draw the base QR = 6 cm.
At point Q draw a ray QX making an ∠ QXR = 60
o
.
Here, PR-PQ = 2cm
PR > PQ
The side containing the base angle Q is less than third side.
2) Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.
3) Join SR and draw its perpendicular bisector ray AB which intersect SR at M.
4) Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.
Thus, △ PQR is the required triangle.
1) Draw the base QR = 6 cm.
At point Q draw a ray QX making an ∠ QXR = 60
o
.
Here, PR-PQ = 2cm
PR > PQ
The side containing the base angle Q is less than third side.
2) Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.
3) Join SR and draw its perpendicular bisector ray AB which intersect SR at M.
4) Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.
Thus, △ PQR is the required triangle.
