Question

Construct a triangle PQR in which PQ+ OR+ PR=10 cm and
angle Q=30° and angle R=60°​

Answer 1

$\huge \mathcal {\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}}}$

ANSWER

Step 1: Draw a line segment AB of 11cm

XY+YZ+ZX=11cm

Step 2: Using a protractor mark 30∘ at A, i.e ∠PAB and ∠QBA as 90∘

Step 3: Bisect 30∘ at A, i.e ∠PAB and ∠QBA at point X. 

Step 4: Join XZ and make XZ  perpendicular to AB.

Step 5: Draw perpendicular bisector of  AX i.e ST.

Step 6: Mark the point Y where ST and AB intersect. Join XY

∴ We get △XYZ 

HOPE SO IT WILL HELP.....

Answer 2

Step-by-step explanation:

$\huge \tt\underline{\text{A} \blue{N} \orange{S} \pink{W} \green{E} \red{R}}:):)$

Steps of Construction:

1. Draw a line segment AB=11 cm. (=PQ+QR+RP).

2. At A, construct an angle of 30° and at B, an angle of 90°

3. Bisect these angles. Let the bisectors of these angles intersect at a point P.

4. Draw perpendicular bisectors DE of AP to intersect AB at Q and FG of PB to intersect AB at R.

5. Join PQ and PR. Then, PQR is the required triangle.

#Somya Here

Smile please ✌️:)