Question

construct a triangle pqr in which PQ +QR RP =10cm , angle Q=30°,angle R =60° with justification


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Answer 1

Answer:

Draw the base QR = 6 cm.

At point Q draw a ray QX making an ∠ QXR = 60

o

.

Here, PR-PQ = 2cm

PR > PQ

The side containing the base angle Q is less than third side.

2) Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.

3) Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

4) Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.

Thus, △ PQR is the required triangle.