Question

Construct a triangle PQR, in which PQ = QR = RP = 6 cm.
step:SUM OF THE TWO SIDES OF TRIANGLES >THIRD SIDE
PQ+QP>RP
6+6>6
6+6>6
6+6>6

Answer 1

Answer:

•Draw the base QR = 6 cm. ...

•Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.

•Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

•Let P be the intersection point of SX and perpendicular bisector AB.