construct a triangle PQR in which Q =90⁰and PQ=4cm and QR= 3CM
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- Draw a rough sketch of the triangle.
- After that ,Draw a line segment QR of 3 cm.
- After that Draw an angle of 90° using compass/protector of 180°
- Next with 4 cm as radius and Q as centre draw an arc on the 90°angle
- Join QP.
Our ∆ is ready :)
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