Question

construct a triangle PQR in which QR= 3.8 cm , angle Q=45 degree and angle R = 60 degree . also, construct the perpendicular to QR from the vertex P.​

Answer 1

Answer:

Answer

Step 1: Draw a line segment AB of 11cm

XY+YZ+ZX=11cm

Step 2: Using a protractor mark 30

∘

at A, i.e ∠PAB and ∠QBA as 90

∘

Step 3: Bisect 30

∘

at A, i.e ∠PAB and ∠QBA at point X.

Step 4: Join XZ and make XZ perpendicular to AB.

Step 5: Draw perpendicular bisector of AX i.e ST.

Step 6: Mark the point Y where ST and AB intersect. Join XY

∴ We get △XYZ .

Hope it helps you and kindly mark the brainli.