Construct a triangle PQR in which QR=4.9cm Q=45^ and PQ+PR=8cm. Write steps of construction.
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Answer:
1)We draw a line segment QR=8cm.
2)Using ruler and compass we construct angle(XQR)=45°.
3)From QX, we cut off QY=3.5cm and YR is joined.
4)We construct the perpendicular bisector EF of YR which when produced to cut QX at the point P and PR is joined.
Thus,PQR is the required
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