Construct a triangle PQR in which Qr = 5.4 cm, Q = 60° and PR - PQ = 2.3 cm and QR=5.4
justify the same. (steps not required)
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Steps of Construction:
(i) Draw a line segment which is sufficiently long using ruler.
(ii) Locate points P and Q on it such that PQ=5.4cm.
(iii) At Q, construct a line segment QS, sufficiently large, such that ∠PQR=55˚ ; use protractor to measure 55˚
(iv) With Q as centre and radius 5.5cm, draw the line cutting QS at R; join PR.
Thus PQR is the required triangle.
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