Question

Construct a triangle pqr in which qr=6 cm angle b=60 and pr-pq=2cm

Answer 1

here is your answer hope it will help you

Answer 2

The below given steps will be followed to construct the required triangle.

Step I: Draw line segment QR of 6 cm. At point Q draw an angle of 60°, say ∠XQR.

Step II: Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. (As PR > PQ and PR - PQ = 2 cm). Join SR.

Step III: Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.

∆PQR is the required triangle.