Question

Construct a triangle PQR in which QR= 6 cm,angle Q = 60oandPR –PQ = 1.5 cm.

Answer 1

Answer:

Step-by-step explanation:    1. Draw the base QR = 6 cm. ...

   2.Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX            extended  on  opposite  side  of  base  QR.

  3. Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

 4.  Let P be the intersection point of SX and perpendicular bisector AB.

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Answer 2

Answer:

construction the straight➖ line pq 1.5 cm

and Q at the angle oof 60 degree

and construction the line QR 6 cm opposite to Q

Step-by-step explanation:

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