Question

Construct a triangle PQR in which QR = 6 cm , <Q = 60° & PR - PQ = 2 cm
With the help of diagram​

Answer 1

Answer:

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Step-by-step explanation:

Draw the base QR = 6 cm.

At the point Q make an ∠XQR = 60°.

Cut line segment QS = PR – PQ (= 2 cm) from the line QX extended on opposite side of line segment QR.

Join SR.

Draw the perpendicular bisector LM of SR.

Let LM intersect QX at P.

Join PR.

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Answer 2

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