Question

Construct a triangle PQR, in which QR = 6 cm, Q = 60° and PR - PQ=2 cm​

Answer 1

• First draw a base of 6 cm
• From point Q draw 60 degree using protractor
• from R draw an arc of 2 cm and join the line . hope you like this answer

Answer 2

Given: 

In ∆PQR, QR= 6 cm, PR-PQ=2 cm & ∠Q= 60°

Steps of construction:

1. Draw the base QR=6 cm.

At Point Q draw a ray QX making an  ∠XQR=60°

Here , PR -PQ= 2cm

PR>PQ

The side containing the base angle Q is less than third side.

 

2. Cut the line segment QS equal to PR-PQ=2 cm , from the ray QX extended on  opposite side of base QR.

3. Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

4. Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.

Thus ∆PQR is the required Triangle.