Construct a triangle pqr in which qr=6cm angle q=30 and pq-pr=3cm
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Step-by-step explanation:
this question is wrong as I tried for so long but any one measure is wrong and try to take measure in place of qr--) 5cm
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29
PQR is a required triangle
Step-by-step explanation:
- Draw a base of length segment QR = 6 cm
- make an angle of 30 degree from Q an draw a line QX .
- open the compass to the length PQ-PR = 3 cm
- From q as a center cut an arc of 3 cm
- let the arc intersect the QX at point D .
- now, draw the perpendicular bisector of RD .
- then join PR.
PQR is a required triangle .
#Learn more:
construct a triangle PQR in which QR=6cm and angle Q = 60degree and PR-PQ=2cm.
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