Construct a triangle pqr in which qr=6cm angle q=60degree and pr-pq=2 cm
Answers
Answer:
the answer of this question is in ncert of class 9th in chapter 9
Step-by-step explanation:
Heya Mate..
1. Draw a line segment QR of length 6 cm.
2. Now, make angle Q=60° with compass and ruler or protractor.
3. Now, extend it to any random length(but much longer).
4. Again, measure 2 cm on your compass and cut the ray of random length. Mark the point as O.
5. Then, using compass and ruler bisect the line segment OR.
6. Now, the point at which the line bisector of OR cuts the random length ray, mark it as point P.
7. At Last, join PR.
:. PQR is your required triangle.
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