Question

construct a triangle pqr in which qr=7 cm angle q=75° and pq-pr=3 cm​

Answer 1

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Answer 2

Answer:

1.Draw base BC=7cm

2.Let's draw ∠B=75∘.Let the ray be BX

3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D

4.Now, we will draw perpendicular bisector of CD

5.Mark point A where perpendicular bisector intersects BD

6.Join AC

7.Result:△ABC is the required triangle.

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