construct a triangle PQR in which QR =7cm, LQ=60°and PR-PQ=2cm
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Answered by
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Answer:
- Draw the base QR = 6 cm. ...
- Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.
- Join SR and draw its perpendicular bisector ray AB which intersect SR at M.
- Let P be the intersection point of SX and perpendicular bisector AB.
it is wrong
have you ever check ? ,
yes
i said 7cm not 6
okay as your wish:)
are what I told to u
what ?
told
Answered by
2
Answer:
1) Draw the base QR = 6 cm.
At point Q draw a ray QX making an ∠ QXR = 60o.
Here, PR-PQ = 2cm
PR > PQ
The side containing the base angle Q is less than third side.
2) Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.
3) Join SR and draw its perpendicular bisector ray AB which intersect SR at M.
4) Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.
Thus, △ PQR is the required triangle.
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it is also wrong
no im right
tellimg wrong
im in genius will I report your profile
it is 7cm not 6
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