Question

Construct a triangle PQR in which QR =7cm <Q=75 and PQ+PR=13cm​

Answer 1

first of all take a line segment QR is equal to 7 cm and angle Q make an angle of 75 degree and cut the line is at 13 cm now join the line s r bisect sr meet at the point P not join the line p r pqr is a required Triangle by following the steps you make get your Triangle

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Answer 2

Here is your answer:

Step-by-step explanation:

1) Draw QR = 7cm

2) construct angle 75 ° and Mark the line X to form QX

3) mark the point D on QX such that QD = 13 cm

4) join DR.

5) Draw perpendicular bisecter of DR. Let it intersect on line BD and mark the point P.

6) Join PR.THE RED MARKED TRIANGLE IS THE REQUIRED TRIANGLE.

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