Question

construct a triangle pqr in which QR equals to 5.8 cm PR minus PQ equal to 1.8 cm and angle Q equals to 45 degree with steps ​

Answer 1

Answer:

Draw the base QR of length 3 cm.

Make an angle XQR = 45° at point Q of base QR.

Cut the line segment QS =QP- PR = 2 cm from the ray QX.

Join SR and draw the perpendicular bisector of SR say AB.

Let bisector AB intersect QX at P. Join PR Thus, ΔPQR is the required triangle.

Step-by-step explanation:

Answer 2

Answer:

construct a triangle PQR in which QR=5.8cm ,PR-PQ=1.8cm and angle Q=45°