Question

construct a triangle pqr in which QR is equal to 6 CM angle Q is equal to 60 degree and PR minus PQ is equal to 2 cm with steps of construction​

Answer 1

Answer:

Step-by-step explanation:

Steps of Construction  

(i) Draw line segment QR of measure 6 cm.  

(ii) At Q construct  an ∠YQR = 60°.  

(iii) Produce YQ to Y' to form line YQY'.

(iv) Cut a line segment QS of 2 cm from the line segment OP’. ( PR > PQ and PQ – PR = 2cm ). Join SR.  

(vi) Draw perpendicular bisector of RS which intersect QY at  P.

(vii) Join PR to obtain required DPQR.  

Justification  

As P lies on the perpendicular bisector of RS.  

Therefore,  PR = PS = PQ + QS = PQ + 2 cm

 ⇒  PR - PQ = 2cm

Hence, △PQR is the required triangle.

Answer 2

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