Question

construct a triangle PQR
QR=5.6
∠Q = 45°
RP= 6.2 cm
make sure to make a figure

Answer 1

Answer:

ANSWER

PQ=6.2cm, ∠Q=60∘ & RQ-PR=3cm

1)Draw PQ of length 6.2cm.

2)Draw ∠Q=60∘.Let the ray be QX.

3)Open the compass to length RQ-PR=3cm.

Since RQ-PR=3cm;

(RQ-PR) is negative

From point Q as centre, cut an arc on ray QX let the arc interect QX at D.

4)Join PD.

5)Now draw perpendicular bisector of PD.

6)Join PR; △ABC is the required △le.

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