construct a triangle PQR such that angle P - 90 PQ - 6 cm QR - 10 cm
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Answer:
Given,
angle P= 90°,PQ=6cm, QR=10cm.
You know that
angle P+PQ+QR= 180°
angle P+6cm+10 cm=180°
angle P+16=180°
angle P=180°-16°
angle P=164°
I hope help you
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