Question

Construct a triangle PQR such that PQ = 5.2 cm, QR = 4.6 cm and

Q= 450​

Answer 1

Answer:

Steps of Construction:

(i) Draw a line segment that is sufficiently long using a ruler.

(ii) Locate points Q and R on it such that QR=5.2cm.

(iii) At Q, construct a line segment QM, sufficiently large, such that ∠MQR at 60

∘

use protractor to measure 60

∘

(iv) With Q as centre and radius 4cm, draw the line cutting QM at P, join PR.

Then PQR is the required triangle.