Question

construct a triangle PQR such that PQ=5cm,PR=3cm and triangle QPR=90° (SAS)​

Answer 1

Given : PQ=5cm,PR=3cm and triangle QPR=90°

To Find : construct   triangle PQR

Solution:

Step 1 : Draw a line segment PQ  = 5 cm

Step 2 : Draw  a right angle at P on PQ using protractor /set square

Step 3 : Take a point at 3 cm from P on angle drawn and mark it as  R

Step 4 : join  QR

Required triangle is constructed.

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