Construct a triangle PQR such that PQ = QR = 7 cm and angle PQR = 45°. What type of a triangle is triangle PQR ( Make sure to write steps-of-construction)
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(i) Draw a line segment PQ of length 6 cm. (ii) With P as centre, draw an arc of radius 4.5 cm. (iii) With Q as centre, draw an arc of radius 7 cm which intersects the previous arc at R. (iv) Join PR and QR. Then ∆PQR is the required triangle.
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1. draw a line PQ of 6 cm ..2. now you can do your questions as it is given
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