Question

Construct a triangle PQR such that R=
PQR such that R = 100⁰, QR=RP=5.4cm
​

Answer 1

Step-by-step explanation:

step1- draw a line segment QR=5.4cm

step2- using proctractor construct 100° with centre of R by drawing RXray

step3- draw an arc of length 5.4 cm with centre of R

step4- point intersection of arc with RX Ray as P

step5- join pq ∆pqr is forming

Answer 2

Step-by-step explanation:

I hope it's help you./////