Question

Construct a triangle PQR, such that sum of its all sides is 10.4 cm ,angle b=60' and angle C=40'​

Answer 1

Answer:

Step-by-step explanation:

Draw a line 10.4 xm long name it BC

Then construct angle 60 at b and 40 at c then bisect these angles

Let they intersect at P draw perpendicular bisector of bp and cp

Let they intersect BC at q and r respectively

Join pq and PR

Thus pqr is required triangle