Construct a triangle PQR, where ∠P=50°, ∠R=40° and PQ=6 cm.
Answers
Answer:
Steps of Construction:
(i) Draw a line segment PQ = 6 cm.
(ii) At P, draw a ray making an angle of 45°
(iii) At Q, draw another ray making an angle of 60° which intersects the first ray at R.
∆ PQR is the required triangle.
On measuring ∠R, it is 75°.
(ii) Steps of Construction :
(i) Draw a line segment QR = 44 cm.
(ii) At Q, draw a ray making an angle of 75°
(iii) At R, draw another arc making an angle of 30° ; which intersects the first ray at R
∆ PQR is the required triangle.
On measuring the lengths of PQ and PR, PQ = 2.1 cm and PR = 4. 4 cm.
(iii) Steps of Construction :
(i) Draw a line segment PR = 5.8 cm
(ii) At P, construct an angle of 60°
(iii) At R, draw another angle of 45° meeting each other at Q.
∆ PQR is the required triangle. On measuring ∠Q, it is 75°
Verification : We know that sum of angles of a triangle is 180°
∴∠P + ∠Q + ∠R = 180°
⇒ 60° + ∠Q + 45° = 180°
⇒ ∠Q + 105° = 180°
⇒ ∠Q = 180° – 105° = 75°.
Step-by-step explanation:
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Answer:
1) First you have to draw a straight line of length 6 cm.
2) Then you need to draw a angle Whose value is 50°
3) Then apply the method of the three angles of a triangle is 180° and calculate the value of the Q. the value will be 90°.
4) Thereafter draw a line and from this you cut 6 cm a straight segment of length.
5) next from the segment's Q point draw a 90°angle.
6) from the opposite point of this segment, P draw 50° angle the drawing above equals an angle of 50°.
7) at last the line from the P point and the Q is increased and It will be seen that they are combined at the point R.
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