Question

construct a triangle PQR where ∆P =60° ∆Q=55° and PQ =4.8cm
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Answer 1

Answer:

Steps of Construction:

(i) Draw a line segment which is sufficiently long using ruler.

(ii) Locate points Q and R on it such that QR=4.8cm.

(iii) Construct a line segment QA, sufficiently large, such that ∠Q=45˚ ;Construct a line segment RB, sufficiently large, such that ∠R=55˚, use protractor to measure

(iv) Extend QA and RB to intersect at P.

Then PQR is the required triangle

Step-by-step explanation:

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