construct a triangle PQR where , PQ = 6 cm QR =8 cm and PR =9 cm
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Step-by-step explanation:
Steps of construction :
1. Draw a line segment PQ=6 cm
2. Draw an arc, using P as a centre and radius 8 cm
3. Draw another arc, using Q as a centre and radius 7 cm
4. Now, join PR and QR to get ΔPQR
5. Draw a ray PX by making an acute angle, angle QPX
6. Divide PX into 4 equal parts.
P
1
,P
2
,P
3
,P
4
,P
5
such PP
1
=P
1
P
2
=P
2
P
3
=P
3
P
4
=P
4
P
5
7. Join P5Q
8. Draw a line P4Q
′
which is parallel to QR
9. Similar to step 8, draw a line Q
′
R
′
which is parallel to QR.
Therefore, ΔPQ
′
R
′
is the required triangle.
solution
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