Question

Construct a triangle PQR whose perimeter is 10.5 cm ND measure of the base angles are 60° and 45° Pls give this answer with clear step by step Tomorrow is my exam.. pls give as fast as possible . I need in step ..

Answer 1

Draw a line XY horizontally.  
Mark a line segment DE of length (perimeter) 10.5 cm on it.  
At D draw a line DW at angle of 60 deg to DE.
At E draw line EV at angle of 45 deg. to DE to meet DW at  P.
Draw a perpendicular bisector of PD to meet DE at Q.
Draw a perpendicular bisector of PE to meet DE at R.

Join PQ and PR.  PQR is the triangle needed.